--> Produced By Quick-Exit
--> SOLVE FOR THE VALUE OF X , Y AND Z USING SIMULTANEOUS EQUATION.
--> SOLVE BY SUBSTITUTION METHOD
--> 2X + 3Y-4Z = 2 EQ(1)
--> 3X + 2Y-2Z = 4 EQ(2)
--> 4X-3Y + 3Z = 2 EQ(3)
--> Produced By Quick-Exit
--> Solve for X in EQ(1)
--> 2X = 2 -1 x 3Y -1 x -4Z EQ(4)
--> 2X = 2 - 3Y + 4Z EQ(4)
--> X = [ 2 - 3Y + 4Z ] / 2 EQ(4)
--> Substitute EQ(4) Into EQ(2) And EQ(3) For X ------->
--> 3X + 2Y-2Z = 4 EQ(2)
--> 4X-3Y + 3Z = 2 EQ(3)
--> ( 3 x [ 2 - 3Y + 4Z ] / 2 ) + 2Y -2Z = 4 EQ(5)
--> ( 4 x [ 2 - 3Y + 4Z ] / 2 ) -3Y + 3Z = 2 EQ(6)
--> 6 -9Y 12Z + 4Y -4Z = 8 EQ(5)
--> -5Y + 8Z = 2 EQ(5)
--> ( 4 x [ 2 - 3Y + 4Z ] / 2 ) -3Y + 3Z = 2 EQ(6)
--> 8 -12Y + 16Z -6Y + 6Z = 4 EQ(6)
--> -18Y + 22Z = -4 EQ(6)
--> Derived Equation
--> -5Y + 8Z = 2 EQ(5)
--> -18Y + 22Z = -4 EQ(6)
--> Produced By Quick-Exit
--> SOLVE FOR THE VALUE OF X AND Y USING SIMULTANEOUS EQUATION.
--> SOLVE SUBSTITUTION METHOD
--> -5Z + 8Y = 2
--> -18Z + 22Y = -4
--> -5Z + 8Y = 2 EQ(1)
--> -18Z + 22Y = -4 EQ(2)
--> Produced By Quick - Exit
--> Solve for X in EQ(1)
--> -5Y = 2 -8Z EQ(3)
--> Produced By Quick - Exit
--> Divide the whole of EQ(3) by -5
--> Y = ( 2 -8Z ) / -5 EQ(3)
--> Substitute EQ(3) into EQ(2) to get Y
--> -18Y + 22Z = -4 EQ(2)
--> -18 x ( 2 -8Z ) / -5 22Z = -4 EQ(4)
--> Multiply the entire equation by the value of the denominator
--> -18 x ( 2 -8Z ) -110Z = 20 EQ(4)
--> Produced By Quick - Exit
--> -36 + 144Z -110Z = 20 EQ(4)
--> -36 + 34Z = 20
--> Conbine like terms together e.g the constant terms
--> 34Z = 56
--> Solve for Y by dividing both sides of the equation by 34
--> 34Z / 34 = 56 / 34
--> Z = 56 / 34
--> Z = 1.64705882352941
--> Z = 1.65
--> Produced By Quick - Exit
--> Solve for X by substituting the value of X into EQ(3)
--> Y = ( 2 -8Z ) / -5 EQ(3)
--> Y = ( 2 -8 x 1.64705882352941 ) / -5 EQ(3)
--> Y = ( 2 + -13.1764705882353 ) / -5 EQ(3)
--> Y = ( -11.1764705882353 ) / -5 EQ(3)
--> Y = 2.23529411764706
--> Produced By Quick - Exit
--> Y = 2.24
--> Check to confirm if the value of X and Y are right using EQ(1) and EQ(2).
-->===================================>
--> -5Y + 8Z = 2 EQ(1)
--> -18Y + 22Z = -4 EQ(2)
--> Produced By Quick - Exit
--> Y = 2.24
--> Z = 1.65
--> -5 x 2.23529411764706 + 8 x 1.64705882352941 = 2 EQ(1)
--> -18 x 2.23529411764706 + 22 x 1.64705882352941 = -4 EQ(2)
--> -11.1764705882353 + 13.1764705882353 = 2 EQ(1)
--> -40.2352941176471 + 36.2352941176471 = -4 EQ(2)
--> Produced By Quick - Exit
--> 2 = 2 EQ(1)
--> -4 = -4 EQ(2)
--> Produced By Quick - Exit
--> Answer for X and Y are correct because the left side is equal to the right side
--> Produced By Quick - Exit
--> Last Stage \ Value Of The Required Variable
--> Solve For The Value Of X In Eq(1)
--> 2X + 3Y -4Z = 2 --> EQ(1)
--> 2X + 3 x 2.23529411764706-4 x 1.64705882352941 = 2 --> EQ(10)
--> 2X + 6.70588235294118 + -6.58823529411765 = 2 --> EQ(10)
--> 2X + 0.11764705882353 = 2 --> EQ(10)
--> 2X = 1.88235294117647 --> EQ(10)
--> X = 1.88235294117647 / 2 --> EQ(10)
--> X = 0.941176470588235 --> EQ(10)
--> X = 0.94
--> The Required Values \ Answers
--> X = 0.94
--> Y = 2.24
--> Z = 1.65
--> Produced By Quick - Exit
--> End Session
--> Produced By Quick-Exit
Checking Stages For Derived \ Given Values \ Answers For X, Y, And Z
Test 1 --> = 3 x 0.94 + 2 x 2.24 + -2 x 1.65
Test 1 --> = 2.82 + 4.48 + -3.3
Test 1 --> = 4
Test 1 --> = 4.00
Test 2 --> = 3 x 0.941176470588235 + 2 x 2.23529411764706 + -2 x 1.64705882352941
Test 2 --> = 2.82352941176471 + 4.47058823529412 + -3.29411764705882
Test 2 --> = 4
Test 2 --> = 4.00
Test 3 --> = 4 x 0.94 + -3 x 2.24 + 3 x 1.65
Test 3 --> = 3.76 + -6.72 + 4.95
Test 3 --> = 1.99
Test 3 --> = 1.99
Test 4 --> = 4 x 0.941176470588235 + -3 x 2.23529411764706 + 3 x 1.64705882352941
Test 4 --> = 3.76470588235294 + -6.70588235294118 + 4.94117647058824
Test 4 --> = 2
Test 4 --> = 2.00
14 - My Heart Will Go On.mp3
