KACL-DS-INC

--> SOLVE FOR THE VALUE OF X AND Y USING SIMULTANEOUS EQUATION. 

--> SOLVE BY SUBSTITUTION METHOD

--> 2X + -3Y = -4

--> 3X + 4Y = 3

--> 2X + -3Y = -4    EQ(1) 

--> 3X + 4Y = 3    EQ(2)  

--> Produced by MATCAL Program 

--> Solve for X in EQ(1)

--> 2X = -4 + 3Y  EQ(3) 

--> Divide the whole of EQ(3) by 2

--> X = ( -4 + 3Y ) / 2  EQ(3) 

--> Substitute EQ(3) into EQ(2) to get Y 

--> Produced by MATCAL Program 

--> 3X + 4Y = 3    EQ(2)  

--> 3 x ( -4 + 3Y ) / 2 + 4Y = 3  EQ(4)

--> Multiply the entire equation by the value of the denominator

--> 3 x ( -4 + 3Y ) + 8Y = 6  EQ(4)

--> -12 + 9Y + 8Y = 6  EQ(4)

--> -12 + 17Y = 6

--> Conbine like terms together e.g the constant terms

--> Produced by MATCAL Program 

--> 17Y = 18

--> Solve for Y by dividing both sides of the equation by  17

--> 17Y / 17 = 18 / 17

--> Y = 18 / 17

--> Y = 1.05882352941176

--> Y = 1.06

--> Solve for X by substituting the value of X into EQ(3)  

--> X = ( -4 + 3Y ) / 2  EQ(3) 

--> X = ( -4 + 3 x 1.05882352941176 ) / 2  EQ(3) 

--> X = ( -4 + 3.17647058823529 ) / 2  EQ(3) 

--> Produced by MATCAL Program 

--> X = ( -0.823529411764706 ) / 2  EQ(3) 

--> X = -0.411764705882353

--> X = -0.41

--> Check to confirm if the value of X and Y are right using EQ(1) and EQ(2).

-->===================================> 

--> Produced by MATCAL Program 

--> 2X + -3Y = -4    EQ(1) 

--> 3X + 4Y = 3    EQ(2)  

--> Produced by MATCAL Program 

--> X = -0.41

--> Y = 1.06

--> 2 x -0.411764705882353 + -3 x 1.05882352941176 = -4    EQ(1) 

--> 3 x -0.411764705882353 + 4 x 1.05882352941176 = 3    EQ(2)  

--> -0.823529411764706 + -3.17647058823529 = -4    EQ(1) 

--> -1.23529411764706 + 4.23529411764706 = 3    EQ(2)  

--> -4 = -4    EQ(1) 

--> 3 = 3    EQ(2)  

--> Answer for X and Y are correct because the left side is equal to the right side

--> Produced by MATCAL Program