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The Joint at point C of the body/beam is a pin
connection for member
AC and Bc to make one Body altogether.
Reverse The Stand/Support For The System/Body
To Be A Different Process / Calculation Entirely.
Horizontal Force Is Equal To = 800 N
Acting angle to the horizontal is equal = 0N/M or
degrees.
Fx = 800 x Cos(64)
Fy = 800 x Sin(64)
Fx = 800 x 0.437967008123867
Fy = 800 x 0.898991045447633
Fx = 350.373606499094
Fy = 719.192836358107
Fx = 350.37 N
Fy = 719.19 N
The rectangular weight/body is = 600 N/M
The triangular weight/body is = 500 N/M
Area of a rectangle = Length x Width = (LW) and area
of a triangle = (base x Height) / 2 ) = bh/2)
Total length of the beam/body = 22.5 M and the
midpoint is = 11.25 M
F1 (From the rectangular weight) = (600 X 12)
F2 (From the triangular weight) = ( 500 x 8 / 2)
F1 (From the rectangular weight) = 7200
F2 (From the triangular weight) = 2000
F1 (From the rectangular weight) = 7,200.00 N
F2 (From the triangular weight) = 2,000.00 N
F2 is distance from the left side is = 1 / 3 x 8
F2 is distance from the right side is = 6 M
F2 is distance from the left side is = 16.5 M
F2 is distance from the left side is =
2.66666666666667 M
F2 is distance from the right side is =
5.33333333333333 M
F2 is distance from the left side is = 2.67 M
F2 is distance from the right side is = 5.33 M
Sum of the forces in X direction is equla to zero.
--> + F(X) = 0 --> Ax - 350.37 = 0 Eqn.(1) --> Ax = 350.37 --> Ax = 350.37 N ^ + F(y) = 0 |
--> Ay + By = 9919.19 Eqn.(2)
--> Ay + By = 9919.19 Eqn.(2)
Sum of the moment at A is equla to zero.
From Left side/hand to the right is positive.
L--> + M(A) = 0
-2.67 x 2000 - 8 x 719.19 - 17 x 7200 + 22.5 x By =
0 Eqn.(3)
-5340 - 5753.52 - 122400 + 22.5 x By = 0 Eqn.(3)
22.5By = 133493.52 Eqn.(3)
By = 133493.52 / 22.5 Eqn.(3)
By = 5933.04533333333
By = 5,933.05
By = 5,933.05 N
From Eqn(2) Above
--> Ay + By = 9919.19 Eqn.(2)
--> Ay = 9919.19 - By Eqn.(2)
--> Ay = 9919.19 - 5933.05
--> Ay = 3986.14
--> Ay = 3986.14 N
--> In solving for member BC, consideration must be
given for the side that has maximum
exerted force on the beam/body and not the smaller
force exerted on the beam/body.
--> Member Bc
^ + F(y) = 0
|
--> Cy + By - 7200 = 0 Eqn.(4)
--> Cy = 7200 - By
--> Cy = 7200 - 5933.05
--> Cy = 1266.95
--> Cy = 1266.95 N
Sum of the forces in X direction is equla to zero.
--> + F(X) = 0
--> Ax - Cx = 0 Eqn.(5)
--> Ax = Cx Eqn.(5)
--> Cx = 350.37 N <--
-------------------------------------------------------------------
--> Ax = 350.37 N
--> Cx = 350.37 N <--
--> Ay = 3986.14 N
--> By = 5,933.05 N
--------------------> SESSION ENDED <--------------------
-------> PRODUCED BY STABMOT SOFTWARE <--------
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